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x(x+1)=9x^2+3
We move all terms to the left:
x(x+1)-(9x^2+3)=0
We multiply parentheses
x^2+x-(9x^2+3)=0
We get rid of parentheses
x^2-9x^2+x-3=0
We add all the numbers together, and all the variables
-8x^2+x-3=0
a = -8; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-8)·(-3)
Δ = -95
Delta is less than zero, so there is no solution for the equation
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